3[7-2(j-8)]=4j+2

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Solution for 3[7-2(j-8)]=4j+2 equation:


Simplifying
3[7 + -2(j + -8)] = 4j + 2

Reorder the terms:
3[7 + -2(-8 + j)] = 4j + 2
3[7 + (-8 * -2 + j * -2)] = 4j + 2
3[7 + (16 + -2j)] = 4j + 2

Combine like terms: 7 + 16 = 23
3[23 + -2j] = 4j + 2
[23 * 3 + -2j * 3] = 4j + 2
[69 + -6j] = 4j + 2

Reorder the terms:
69 + -6j = 2 + 4j

Solving
69 + -6j = 2 + 4j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-4j' to each side of the equation.
69 + -6j + -4j = 2 + 4j + -4j

Combine like terms: -6j + -4j = -10j
69 + -10j = 2 + 4j + -4j

Combine like terms: 4j + -4j = 0
69 + -10j = 2 + 0
69 + -10j = 2

Add '-69' to each side of the equation.
69 + -69 + -10j = 2 + -69

Combine like terms: 69 + -69 = 0
0 + -10j = 2 + -69
-10j = 2 + -69

Combine like terms: 2 + -69 = -67
-10j = -67

Divide each side by '-10'.
j = 6.7

Simplifying
j = 6.7

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